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ICAR JRF Plant Science Practice Series Memory Based PYQ with Explanation

ICAR JRF Plant Science Practice Series Memory Based 2024 (Module 1) (1 – 40 MCQ) 

Question 1

The purine and pyrimidine pairing in DNA is as follows:

  1. A—T, G—C
  2. A—C, T—G
  3. A—T, G—C 
  4. A—G, T—C

Correct Answer: 1

Explanation:

  • Polyploidy – The condition of having more than two sets of chromosomes.
  • Autopolyploid – All chromosome sets come from the same species.
    • Example: Triploid banana (AAA), tetraploid potato (AAAA).
    • Caused by: Failure of meiosis (unreduced gametes) or mitotic doubling.
    • Characteristics: Increased cell size, larger flowers/fruits, but often reduced fertility due to pairing problems.
  • Allopolyploid – Chromosome sets come from different species (interspecific hybridization followed by chromosome doubling).
    • Example: Wheat (AABBDD), cotton (AADD), rapeseed (AACC).
  • Diploid – Two sets of chromosomes.
  • Tetraploid – Four sets (can be auto or allo).

 

 

Question 2

The largest area in India is occupied by the soil group:

  1. Black soil
  2. Red soil
  3. Alluvial soil
  4. Lateritic soil

Correct Answer: 3

Explanation:

  • Alluvial soil– Covers the largest area in India (about 43% of the total land area). Found in the Indo-Gangetic plains and river deltas.
  • Black soil– Found in Deccan Plateau (cotton-growing region).
  • Red soil– Found in Tamil Nadu, Karnataka, Andhra Pradesh.
  • Lateritic soil– Found in high-rainfall areas (Western Ghats, Northeast).
  • Therefore, the correct answer is Alluvial soil→ Option 3.

 

 

Question 3

The cell cycle passes through following stages:

  1. G₁ phase → S → G₂ → Division
  2. S phase → G₁ → G₂ → Division
  3. G₁ phase → G₂ → S → Division
  4. G₂ phase → G₁ → S → Division

Correct Answer: 1

Explanation:

  • The correct order of the cell cycleis:
    • G₁ phase(Gap 1) – Cell growth, protein synthesis.
    • S phase(Synthesis) – DNA replication.
    • G₂ phase(Gap 2) – Preparation for mitosis.
    • M phase (Division)– Mitosis and cytokinesis.
  • Therefore, the correct answer is G₁ phase → S → G₂ → Division→ Option 1.

 

 

Question 4

Biggest organelle of plant cell is:

  1. Mitochondria
  2. Chloroplast
  3. Cytosome
  4. Glycosomes

Correct Answer: 2

 

Explanation:

  • Chloroplast– The largest organelle in plant cells (up to 10 µm in length). It is the site of photosynthesis.
  • Mitochondria– Smaller than chloroplasts (0.5–1 µm).
  • Cytosome– Not a standard organelle (refers to the cell body).
  • Glycosomes– Small microbodies involved in metabolism.
  • Therefore, the correct answer is Chloroplast→ Option 2.

 

 

Question 5

Which one of the following process is called as a necessary evil?

  1. Respiration
  2. Transpiration
  3. Photosynthesis
  4. Translocation

Correct Answer: 2

Explanation:

  • Transpiration– The loss of water vapor from plant surfaces. It is called a “necessary evil” because it is essential for:
    • Cooling the plant.
    • Creating transpiration pull for water and mineral uptake.
    • However, it also causes water loss, which can be harmful under drought conditions.
  • Respiration, photosynthesis, translocation– Not referred to as necessary evil.
  • Therefore, the correct answer is Transpiration→ Option 2.

 

 

Question 6

Blossom end rot in tomato is caused by the deficiency of:

  1. Ca
  2. Mg
  3. Mo
  4. B

Correct Answer: 1

Explanation:

  • Blossom end rot– A physiological disorder in tomato, pepper, and other fruits caused by calcium (Ca) deficiency. Symptoms appear as a dark, sunken lesion at the blossom end of the fruit.
  • Mg– Interveinal chlorosis.
  • Mo– Whiptail in cauliflower.
  • B– Cracked stem, black tip of mango.
  • Therefore, the correct answer is Ca→ Option 1.

 

 

Question 7

Intensification of crops in both time and space dimension refers to:

  1. Sequential cropping
  2. Double cropping
  3. Intercropping
  4. Monocropping

Correct Answer: 3

Explanation:

  • Intercropping– Growing two or more crops simultaneously on the same piece of land. It intensifies cropping in both time and space dimensions.
  • Sequential cropping– Growing crops one after another (time dimension only).
  • Double cropping– Growing two crops in a year (time dimension only).
  • Monocropping– Growing only one crop (no intensification).
  • Therefore, the correct answer is Intercropping→ Option 3.

 

 

Question 8

RNA molecule which acts as enzymes are called as:

  1. Isozyme
  2. Co-enzyme
  3. Ribozyme
  4. Eponezyme

Correct Answer: 3

Explanation:

  • Ribozyme– An RNA molecule that has catalytic activity (acts as an enzyme). Examples include self-splicing introns and ribonuclease P.
  • Isozyme– Different forms of the same enzyme (protein).
  • Co-enzyme– Organic cofactor that assists enzymes.
  • Eponezyme– Not a standard term.
  • Therefore, the correct answer is Ribozyme→ Option 3.

 

 

Question 9

Gibberellic acid is sprayed to hybrid rice seed production plots for:

  1. Delayed flowering
  2. Enhanced flowering
  3. To induce flowering
  4. Complete exertion of panicle

Correct Answer: 4

Explanation:

  • Gibberellic acid (GA₃)– Sprayed on rice panicles to enhance panicle exertion (emergence) from the flag leaf sheath. This is critical in hybrid seed production (especially for CMS lines where panicle exertion is poor).
  • Delayed/enhanced/induced flowering– Not the primary purpose.
  • Therefore, the correct answer is Complete exertion of panicle→ Option 4.

 

 

Question 10

Energy currency of a cell is:

  1. ATP
  2. CTP
  3. GTP
  4. TTP

Correct Answer: 1

Explanation:

  • ATP (Adenosine Triphosphate)is universally known as the energy currency of the cell because it stores and transfers chemical energy for cellular processes.
  • Hydrolysis of ATP to ADP + Pi releases energy (≈7.3 kcal/mol) used in metabolism, transport, and mechanical work.
  • CTP, GTP, TTP– Other nucleotide triphosphates are used in specific processes (e.g., GTP in protein synthesis) but not as the primary energy currency.
  • Therefore, the correct answer is ATP→ Option 1.

 

 

Question 11

Chromosomal theory of inheritance was proposed by:

  1. Mendel
  2. Sutton-Boveri
  3. Morgan
  4. Darwin

Correct Answer: 2

Explanation:

  • The Chromosomal Theory of Inheritancewas independently proposed by Walter Sutton (1902) and Theodor Boveri (1902-1904) .
  • They proposed that genes are located on chromosomes and that the behavior of chromosomes during meiosis explains Mendel’s laws.
  • Mendel– Discovered the laws of inheritance but did not know about chromosomes.
  • Morgan– Worked on linkage and crossing over in Drosophila.
  • Darwin– Proposed the theory of evolution.
  • Therefore, the correct answer is Sutton-Boveri→ Option 2.

 

 

Question 12

Who coined the term cell?

  1. Robert Hooke
  2. Stephen Hales
  3. Priestley
  4. Blackman

Correct Answer: 1

Explanation:

  • Robert Hooke (1665)– Observed cork under a compound microscope and coined the term “cell” (Latin cella, meaning small room) because the structures resembled small chambers.
  • Stephen Hales– Worked on plant physiology (transpiration, root pressure).
  • Priestley– Discovered oxygen and photosynthesis.
  • Blackman– Formulated the law of limiting factors.
  • Therefore, the correct answer is Robert Hooke→ Option 1.

 

 

Question 13

The eminent feature that differentiates Angiosperm from Gymnosperm seed is:

  1. Seed coat
  2. Embryo
  3. Endosperm
  4. Cotyledon

Correct Answer: 3

Explanation:

  • Angiosperm seeds– The endosperm is triploid (3n) , formed by double fertilization (fusion of one sperm with two polar nuclei).
  • Gymnosperm seeds– The endosperm is haploid (n) , formed from the female gametophyte (pre-fertilization).
  • Seed coat, embryo, cotyledons– Present in both groups, not differentiating features.
  • Therefore, the correct answer is Endosperm→ Option 3.

 

 

Question 14

The term heterosis was coined by:

  1. Shull
  2. Johannsen
  3. Davenport
  4. Morgan

Correct Answer: 1

Explanation:

  • Heterosis– The superiority of F₁ hybrids over their parents. The term was coined by George H. Shull (1914).
  • Johannsen– Coined the terms “gene,” “genotype,” and “phenotype”.
  • Davenport– Proposed the dominance hypothesis of heterosis.
  • Morgan– Worked on linkage and crossing over.
  • Therefore, the correct answer is Shull→ Option 1.

 

 

Question 15

Stomata found on upper surface of leaf are called as:

  1. Hypostomatous
  2. Epistomatous
  3. Amphistomatous
  4. Epicuticular

Correct Answer: 2

Explanation:

  • Epistomatous (Epistomatic)– Stomata present only on the upper (adaxial) surface of the leaf.
  • Hypostomatous– Stomata present only on the lower (abaxial) surface (most dicots).
  • Amphistomatous– Stomata present on both surfaces (many monocots, some dicots).
  • Epicuticular– Refers to the wax layer on the leaf surface, not stomata.
  • Therefore, the correct answer is Epistomatous→ Option 2.

 

 

Question 16

Green ear symptom of bajra is due to:

  1. Rust
  2. Ergot
  3. Downy mildew
  4. Leaf blight

Correct Answer: 3

Explanation:

  • Green ear of bajra (pearl millet)is caused by the downy mildew fungus Sclerospora graminicola.
  • The inflorescence is transformed into green, leafy structures (phyllody), resembling a “green ear”.
  • Rust– Caused by Puccinia (pustules).
  • Ergot– Caused by Claviceps (honeydew and sclerotia).
  • Leaf blight– Caused by Helminthosporium or Bipolaris.
  • Therefore, the correct answer is Downy mildew→ Option 3.

 

 

Question 17

The number of characters selected by Mendel for his study is:

  1. 5
  2. 10
  3. 7
  4. 22

Correct Answer: 3

Explanation:

  • Mendel studied 7 charactersin pea (Pisum sativum):
    1. Seed shape (round/wrinkled)
    2. Seed colour (yellow/green)
    3. Flower colour (purple/white)
    4. Pod shape (inflated/constricted)
    5. Pod colour (green/yellow)
    6. Flower position (axial/terminal)
    7. Stem height (tall/dwarf)
  • Therefore, the correct answer is 7→ Option 3.

 

 

Question 18

Which of the following is only minimally absorbed by chlorophylls a and b?

  1. Violet light
  2. Green light
  3. Blue light
  4. Red light

Correct Answer: 2

Explanation:

  • Chlorophylls a and babsorb light most strongly in the blue (430-450 nm) and red (640-680 nm)
  • Green light (500-600 nm)is minimally absorbed and is mostly reflected, which is why plants appear green.
  • Violet light– Absorbed moderately.
  • Therefore, the correct answer is Green light→ Option 2.

 

 

Question 19

White bud of maize is due to:

  1. Mg
  2. Zn
  3. Ca
  4. Fe

Correct Answer: 2

Explanation:

  • White bud of maizeis caused by zinc (Zn) deficiency.
  • Symptoms: Young leaves become pale yellow to white (bleached), especially near the base; internodes shorten; plants may die.
  • Mg– Interveinal chlorosis in older leaves.
  • Ca– Death of growing points, leaf tip burn.
  • Fe– Interveinal chlorosis in young leaves.
  • Therefore, the correct answer is Zn→ Option 2.

 

 

Question 20

Plant virus containing DNA is:

  1. Potato mosaic virus
  2. Tobacco mosaic virus
  3. Cauliflower mosaic virus
  4. Papaya ring spot virus

Correct Answer: 3

Explanation:

  • Cauliflower mosaic virus (CaMV)– A dsDNA (double-stranded DNA) virus, belonging to the family Caulimoviridae.
  • Potato mosaic virus, Tobacco mosaic virus (TMV), Papaya ring spot virus– All have ssRNA
  • Therefore, the correct answer is Cauliflower mosaic virus→ Option 3.

 

 

Question 21

The modern technique for varietal identification is:

  1. Electrophoresis
  2. Grow-out test
  3. Phenol test
  4. Polysaccharide

Correct Answer: 1

Explanation:

  • Electrophoresis– A modern, rapid, and reliable technique for varietal identification based on protein or DNA banding patterns.
  • Grow-out test– Traditional field test for genetic purity (time-consuming).
  • Phenol test– Chemical test for seed colour reaction (limited to certain crops).
  • Polysaccharide– Not a varietal identification technique.
  • Therefore, the correct answer is Electrophoresis→ Option 1.

 

 

Question 22

Light reactions of photosynthesis take place in:

  1. Cristae
  2. Cytoplasm
  3. Mitochondria
  4. Thylakoids

Correct Answer: 4

Explanation:

  • Light reactions(light-dependent reactions) of photosynthesis occur in the thylakoid membranes of chloroplasts (containing chlorophyll and other pigments).
  • Cristae– Inner mitochondrial membrane.
  • Cytoplasm– Site of glycolysis.
  • Mitochondria– Site of cellular respiration.
  • Therefore, the correct answer is Thylakoids→ Option 4.

 

 

Question 23

Noble cane is:

  1. Saccharum officinarum
  2. Saccharum robustum
  3. Saccharum sinense
  4. Saccharum spontaneum

Correct Answer: 1

Explanation:

  • Noble cane– Refers to Saccharum officinarum, which has thick stems, high sugar content, and is the primary cultivated sugarcane species.
  • robustum– A wild relative, thick but low sugar.
  • sinense– Thin, hardy, used in some regions.
  • spontaneum– Wild, thin, low sugar, used in breeding for hardiness.
  • Therefore, the correct answer is Saccharum officinarum→ Option 1.

 

 

Question 24

The enzyme responsible for prediction of viability through Tetrazolium test is:

  1. Peroxidase
  2. Amylase
  3. Super oxide dismutase
  4. Dehydrogenase

Correct Answer: 4

Explanation:

  • Tetrazolium test (TZ test)– A seed viability test that uses 2,3,5-triphenyl tetrazolium chloride.
  • The test is based on the activity of dehydrogenase enzymesin living tissues. Dehydrogenases reduce the colorless tetrazolium salt to red formazan.
  • Peroxidase, amylase, superoxide dismutase– Not detected by TZ test.
  • Therefore, the correct answer is Dehydrogenase→ Option 4.

 

 

Question 25

An Alloaugamous oilseed is:

  1. Safflower
  2. Groundnut
  3. Sesame
  4. Mustard

Correct Answer: 1

Explanation:

  • Alloaugamous– A plant that is cross-pollinated (allogamous). Among oilseeds, safflower is cross-pollinated (pollinated by insects).
  • Groundnut, sesame, mustard– Primarily self-pollinated (autogamous).
  • Therefore, the correct answer is Safflower→ Option 1.

 

 

Question 26

The ecological suicide of the crop seeds occur at field due to accumulation of:

  1. HCN
  2. Ethylene
  3. Carbon monoxide
  4. Carbon disulphide

Correct Answer: 1

Explanation:

  • Ecological suicide– Germination of seeds in the field under unfavorable conditions (e.g., after rainfall) followed by desiccation, leading to death.
  • In some crops (e.g., sorghum), seeds can accumulate HCN (hydrogen cyanide), which can cause toxicity. However, “ecological suicide” often refers to premature germination (vivipary) or seed death.
  • Given the options, HCNis associated with seed toxicity.
  • Therefore, the correct answer is HCN→ Option 1.

 

 

Question 27

The element which is involved in energy transfer and storage in plants is:

  1. N
  2. P
  3. K
  4. Ca

Correct Answer: 2

Explanation:

  • Phosphorus (P)– A key component of ATP (energy currency) , NADPH, and other energy-transfer molecules. It is also part of nucleic acids and phospholipids.
  • N– Component of proteins, nucleic acids.
  • K– Osmotic regulation, enzyme activation.
  • Ca– Cell wall structure, signaling.
  • Therefore, the correct answer is P→ Option 2.

 

 

Question 28

Synaptonemal complex appears during:

  1. Leptotene
  2. Zygotene
  3. Diakinesis
  4. Diplotene

Correct Answer: 2

Explanation:

  • Synaptonemal complex– A protein structure that forms between homologous chromosomes during synapsis.
  • It appears during zygotene(the stage of prophase I where homologous chromosomes begin to pair).
  • Leptotene– Chromosomes condense; no pairing.
  • Diakinesis– Terminalization of chiasmata.
  • Diplotene– Chiasmata visible, homologous chromosomes begin to separate.
  • Therefore, the correct answer is Zygotene→ Option 2.

 

 

Question 29

The second generation Bt cotton contains genes of:

  1. Cry 1 Ac, Cry 2 Ab
  2. Cry 2 Ac, 2 Ab
  3. Cry 2 Ac, Cry 1 Ab
  4. Cry 1 Ac, 1 Ab

Correct Answer: 1

Explanation:

  • First generation Bt cotton– Contained a single gene, Cry 1 Ac (active against bollworms).
  • Second generation Bt cotton– Contains two genes: Cry 1 Ac and Cry 2 Ab (or Cry 1 Ac and Cry 2 Ab) for better insect resistance and to delay resistance development.
  • Therefore, the correct answer is Cry 1 Ac, Cry 2 Ab→ Option 1.

 

 

Question 30

Masanobu Fukuoka is the pioneer of:

  1. Conservation farming
  2. Organic farming
  3. Natural farming
  4. Chemical farming

Correct Answer: 3

Explanation:

  • Masanobu Fukuoka (1913-2008)– A Japanese farmer and philosopher, known as the pioneer of “Natural Farming” (do-nothing farming) .
  • His method emphasizes no tillage, no fertilizers, no pesticides, and no weeding (as much as possible).
  • Conservation farming– Focuses on soil conservation.
  • Organic farming– Avoids synthetic inputs but may use tillage.
  • Chemical farming– Conventional agriculture.
  • Therefore, the correct answer is Natural farming→ Option 3.

 

 

Question 31

Azure blue colour tag is enclosed with the seed bag of:

  1. Certified seed
  2. Foundation seed
  3. Breeder seed
  4. Nucleus seed

Correct Answer: 3

Explanation:

  • In the Indian seed certification system:
    • Breeder seed– Azure blue
    • Foundation seed– White tag.
    • Certified seed– Golden brown (or blue for some crops).
    • Nucleus seed– No tag.
  • Therefore, the correct answer is Breeder seed→ Option 3.

 

 

Question 32

The enzyme involved in transcription is:

  1. RNA polymerase
  2. Taq polymerase
  3. DNA polymerase I
  4. DNA polymerase III

Correct Answer: 1

Explanation:

  • Transcription– The process of synthesizing RNA from a DNA template. It is catalyzed by RNA polymerase.
  • Taq polymerase– Used in PCR (DNA amplification).
  • DNA polymerase I and III– Involved in DNA replication.
  • Therefore, the correct answer is RNA polymerase→ Option 1.

 

 

Question 33

The highest % N is present in:

  1. Urea
  2. Ammonium nitrate
  3. Urea sulphate
  4. Anhydrous ammonia

Correct Answer: 4

Explanation:

  • Anhydrous ammonia (NH₃)– Contains 82% N (highest among nitrogenous fertilizers).
  • Urea (CO(NH₂)₂)– Contains 46% N.
  • Ammonium nitrate (NH₄NO₃)– Contains 33-35% N.
  • Urea sulphate– Lower N content (around 30-35%).
  • Therefore, the correct answer is Anhydrous ammonia→ Option 4.

 

 

Question 34

Seed Act was formulated and enacted during:

  1. 1966 and 1968
  2. 1966 and 1969
  3. 1963 and 1966
  4. 1988 and 1990

Correct Answer: 1

Explanation:

  • The Seeds Act, 1966was passed by the Indian Parliament in 1966 and came into force in 1968.
  • It regulates the quality of seeds sold in India and establishes the Central Seed Certification Board.
  • Therefore, the correct answer is 1966 and 1968→ Option 1.

 

 

Question 35

The total number of codons are:

  1. 60
  2. 62
  3. 64
  4. 66

Correct Answer: 3

Explanation:

  • The genetic code consists of 64 codons(triplet combinations of four nucleotides: 4³ = 64).
  • Out of these, 61 codonscode for amino acids, and 3 codons are stop codons (UAA, UAG, UGA).
  • Therefore, the correct answer is 64→ Option 3.

 

 

Question 36

Which state leads in acreage and productivity of Indian mustard?

  1. Rajasthan
  2. Madhya Pradesh
  3. Punjab
  4. Uttar Pradesh

Correct Answer: 1

Explanation:

  • Rajasthanis the leading state in India in terms of both acreage and productivity of Indian mustard (Brassica juncea).
  • The state accounts for nearly 50% of the total mustard area in India.
  • Madhya Pradesh, Punjab, Uttar Pradesh– Also produce mustard but less than Rajasthan.
  • Therefore, the correct answer is Rajasthan→ Option 1.

 

 

Question 37

An example for slow releasing N fertilizer is:

  1. S coated urea
  2. AM
  3. N serve
  4. PSB

Correct Answer: 1

Explanation:

  • S coated urea (Sulfur-coated urea)– A slow-release nitrogen fertilizer. The sulfur coating gradually breaks down, releasing urea slowly over time.
  • AM– Not a standard slow-release fertilizer.
  • N serve (Nitrapyrin)– A nitrification inhibitor, not a slow-release fertilizer.
  • PSB (Phosphate Solubilizing Bacteria)– Biofertilizer for phosphorus.
  • Therefore, the correct answer is S coated urea→ Option 1.

 

 

Question 38

During DNA replication, the enzyme which separates the two sides of the helix is called as:

  1. DNA polymerase
  2. DNA amylase
  3. DNA ligase
  4. DNA helicase

Correct Answer: 4

Explanation:

  • DNA helicase– The enzyme that unwinds and separates the two strands of the DNA double helix by breaking hydrogen bonds between base pairs.
  • DNA polymerase– Synthesizes new DNA strands.
  • DNA ligase– Joins Okazaki fragments.
  • DNA amylase– Not a real enzyme (amylase breaks down starch).
  • Therefore, the correct answer is DNA helicase→ Option 4.

 

 

Question 39

The Electron Microscope was invented by:

  1. Knoll and Ruska
  2. Clark and Adams
  3. Watson and Crick
  4. Robert Koch

Correct Answer: 1

Explanation:

  • The electron microscopewas invented by Ernst Ruska and Max Knoll in 1931.
  • Ruskareceived the Nobel Prize in Physics in 1986 for this invention.
  • Watson and Crick– Discovered DNA double helix.
  • Robert Koch– Developed Koch’s postulates.
  • Therefore, the correct answer is Knoll and Ruska→ Option 1.

 

 

Question 40

Barbara McClintock was awarded Nobel Prize in 1984 for the discovery of:

  1. Split genes
  2. Pseudo genes
  3. Jumping genes
  4. Overlapping genes

Correct Answer: 3

Explanation:

  • Barbara McClintockdiscovered transposable elements (jumping genes) in maize (corn) in the 1940s-1950s.
  • She was awarded the Nobel Prize in Physiology or Medicine in 1983(not 1984; the question has a typo).
  • Split genes– Discovered by Richard Roberts and Phillip Sharp (Nobel 1993).
  • Pseudo genes– Non-functional copies of genes.
  • Overlapping genes– Genes that share nucleotide sequences.
  • Therefore, the correct answer is Jumping genes→ Option 3.
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