ICAR JRF Plant Science Practice Series Memory Based 2024 (Module 1) (1 – 40 MCQ)
Question 1
The purine and pyrimidine pairing in DNA is as follows:
- A—T, G—C
- A—C, T—G
- A—T, G—C
- A—G, T—C
Correct Answer: 1
Explanation:
- Polyploidy – The condition of having more than two sets of chromosomes.
- Autopolyploid – All chromosome sets come from the same species.
- Example: Triploid banana (AAA), tetraploid potato (AAAA).
- Caused by: Failure of meiosis (unreduced gametes) or mitotic doubling.
- Characteristics: Increased cell size, larger flowers/fruits, but often reduced fertility due to pairing problems.
- Allopolyploid – Chromosome sets come from different species (interspecific hybridization followed by chromosome doubling).
- Example: Wheat (AABBDD), cotton (AADD), rapeseed (AACC).
- Diploid – Two sets of chromosomes.
- Tetraploid – Four sets (can be auto or allo).
Question 2
The largest area in India is occupied by the soil group:
- Black soil
- Red soil
- Alluvial soil
- Lateritic soil
Correct Answer: 3
Explanation:
- Alluvial soil– Covers the largest area in India (about 43% of the total land area). Found in the Indo-Gangetic plains and river deltas.
- Black soil– Found in Deccan Plateau (cotton-growing region).
- Red soil– Found in Tamil Nadu, Karnataka, Andhra Pradesh.
- Lateritic soil– Found in high-rainfall areas (Western Ghats, Northeast).
- Therefore, the correct answer is Alluvial soil→ Option 3.
Question 3
The cell cycle passes through following stages:
- G₁ phase → S → G₂ → Division
- S phase → G₁ → G₂ → Division
- G₁ phase → G₂ → S → Division
- G₂ phase → G₁ → S → Division
Correct Answer: 1
Explanation:
- The correct order of the cell cycleis:
- G₁ phase(Gap 1) – Cell growth, protein synthesis.
- S phase(Synthesis) – DNA replication.
- G₂ phase(Gap 2) – Preparation for mitosis.
- M phase (Division)– Mitosis and cytokinesis.
- Therefore, the correct answer is G₁ phase → S → G₂ → Division→ Option 1.
Question 4
Biggest organelle of plant cell is:
- Mitochondria
- Chloroplast
- Cytosome
- Glycosomes
Correct Answer: 2
Explanation:
- Chloroplast– The largest organelle in plant cells (up to 10 µm in length). It is the site of photosynthesis.
- Mitochondria– Smaller than chloroplasts (0.5–1 µm).
- Cytosome– Not a standard organelle (refers to the cell body).
- Glycosomes– Small microbodies involved in metabolism.
- Therefore, the correct answer is Chloroplast→ Option 2.
Question 5
Which one of the following process is called as a necessary evil?
- Respiration
- Transpiration
- Photosynthesis
- Translocation
Correct Answer: 2
Explanation:
- Transpiration– The loss of water vapor from plant surfaces. It is called a “necessary evil” because it is essential for:
- Cooling the plant.
- Creating transpiration pull for water and mineral uptake.
- However, it also causes water loss, which can be harmful under drought conditions.
- Respiration, photosynthesis, translocation– Not referred to as necessary evil.
- Therefore, the correct answer is Transpiration→ Option 2.
Question 6
Blossom end rot in tomato is caused by the deficiency of:
- Ca
- Mg
- Mo
- B
Correct Answer: 1
Explanation:
- Blossom end rot– A physiological disorder in tomato, pepper, and other fruits caused by calcium (Ca) deficiency. Symptoms appear as a dark, sunken lesion at the blossom end of the fruit.
- Mg– Interveinal chlorosis.
- Mo– Whiptail in cauliflower.
- B– Cracked stem, black tip of mango.
- Therefore, the correct answer is Ca→ Option 1.
Question 7
Intensification of crops in both time and space dimension refers to:
- Sequential cropping
- Double cropping
- Intercropping
- Monocropping
Correct Answer: 3
Explanation:
- Intercropping– Growing two or more crops simultaneously on the same piece of land. It intensifies cropping in both time and space dimensions.
- Sequential cropping– Growing crops one after another (time dimension only).
- Double cropping– Growing two crops in a year (time dimension only).
- Monocropping– Growing only one crop (no intensification).
- Therefore, the correct answer is Intercropping→ Option 3.
Question 8
RNA molecule which acts as enzymes are called as:
- Isozyme
- Co-enzyme
- Ribozyme
- Eponezyme
Correct Answer: 3
Explanation:
- Ribozyme– An RNA molecule that has catalytic activity (acts as an enzyme). Examples include self-splicing introns and ribonuclease P.
- Isozyme– Different forms of the same enzyme (protein).
- Co-enzyme– Organic cofactor that assists enzymes.
- Eponezyme– Not a standard term.
- Therefore, the correct answer is Ribozyme→ Option 3.
Question 9
Gibberellic acid is sprayed to hybrid rice seed production plots for:
- Delayed flowering
- Enhanced flowering
- To induce flowering
- Complete exertion of panicle
Correct Answer: 4
Explanation:
- Gibberellic acid (GA₃)– Sprayed on rice panicles to enhance panicle exertion (emergence) from the flag leaf sheath. This is critical in hybrid seed production (especially for CMS lines where panicle exertion is poor).
- Delayed/enhanced/induced flowering– Not the primary purpose.
- Therefore, the correct answer is Complete exertion of panicle→ Option 4.
Question 10
Energy currency of a cell is:
- ATP
- CTP
- GTP
- TTP
Correct Answer: 1
Explanation:
- ATP (Adenosine Triphosphate)is universally known as the energy currency of the cell because it stores and transfers chemical energy for cellular processes.
- Hydrolysis of ATP to ADP + Pi releases energy (≈7.3 kcal/mol) used in metabolism, transport, and mechanical work.
- CTP, GTP, TTP– Other nucleotide triphosphates are used in specific processes (e.g., GTP in protein synthesis) but not as the primary energy currency.
- Therefore, the correct answer is ATP→ Option 1.
Question 11
Chromosomal theory of inheritance was proposed by:
- Mendel
- Sutton-Boveri
- Morgan
- Darwin
Correct Answer: 2
Explanation:
- The Chromosomal Theory of Inheritancewas independently proposed by Walter Sutton (1902) and Theodor Boveri (1902-1904) .
- They proposed that genes are located on chromosomes and that the behavior of chromosomes during meiosis explains Mendel’s laws.
- Mendel– Discovered the laws of inheritance but did not know about chromosomes.
- Morgan– Worked on linkage and crossing over in Drosophila.
- Darwin– Proposed the theory of evolution.
- Therefore, the correct answer is Sutton-Boveri→ Option 2.
Question 12
Who coined the term cell?
- Robert Hooke
- Stephen Hales
- Priestley
- Blackman
Correct Answer: 1
Explanation:
- Robert Hooke (1665)– Observed cork under a compound microscope and coined the term “cell” (Latin cella, meaning small room) because the structures resembled small chambers.
- Stephen Hales– Worked on plant physiology (transpiration, root pressure).
- Priestley– Discovered oxygen and photosynthesis.
- Blackman– Formulated the law of limiting factors.
- Therefore, the correct answer is Robert Hooke→ Option 1.
Question 13
The eminent feature that differentiates Angiosperm from Gymnosperm seed is:
- Seed coat
- Embryo
- Endosperm
- Cotyledon
Correct Answer: 3
Explanation:
- Angiosperm seeds– The endosperm is triploid (3n) , formed by double fertilization (fusion of one sperm with two polar nuclei).
- Gymnosperm seeds– The endosperm is haploid (n) , formed from the female gametophyte (pre-fertilization).
- Seed coat, embryo, cotyledons– Present in both groups, not differentiating features.
- Therefore, the correct answer is Endosperm→ Option 3.
Question 14
The term heterosis was coined by:
- Shull
- Johannsen
- Davenport
- Morgan
Correct Answer: 1
Explanation:
- Heterosis– The superiority of F₁ hybrids over their parents. The term was coined by George H. Shull (1914).
- Johannsen– Coined the terms “gene,” “genotype,” and “phenotype”.
- Davenport– Proposed the dominance hypothesis of heterosis.
- Morgan– Worked on linkage and crossing over.
- Therefore, the correct answer is Shull→ Option 1.
Question 15
Stomata found on upper surface of leaf are called as:
- Hypostomatous
- Epistomatous
- Amphistomatous
- Epicuticular
Correct Answer: 2
Explanation:
- Epistomatous (Epistomatic)– Stomata present only on the upper (adaxial) surface of the leaf.
- Hypostomatous– Stomata present only on the lower (abaxial) surface (most dicots).
- Amphistomatous– Stomata present on both surfaces (many monocots, some dicots).
- Epicuticular– Refers to the wax layer on the leaf surface, not stomata.
- Therefore, the correct answer is Epistomatous→ Option 2.
Question 16
Green ear symptom of bajra is due to:
- Rust
- Ergot
- Downy mildew
- Leaf blight
Correct Answer: 3
Explanation:
- Green ear of bajra (pearl millet)is caused by the downy mildew fungus Sclerospora graminicola.
- The inflorescence is transformed into green, leafy structures (phyllody), resembling a “green ear”.
- Rust– Caused by Puccinia (pustules).
- Ergot– Caused by Claviceps (honeydew and sclerotia).
- Leaf blight– Caused by Helminthosporium or Bipolaris.
- Therefore, the correct answer is Downy mildew→ Option 3.
Question 17
The number of characters selected by Mendel for his study is:
- 5
- 10
- 7
- 22
Correct Answer: 3
Explanation:
- Mendel studied 7 charactersin pea (Pisum sativum):
- Seed shape (round/wrinkled)
- Seed colour (yellow/green)
- Flower colour (purple/white)
- Pod shape (inflated/constricted)
- Pod colour (green/yellow)
- Flower position (axial/terminal)
- Stem height (tall/dwarf)
- Therefore, the correct answer is 7→ Option 3.
Question 18
Which of the following is only minimally absorbed by chlorophylls a and b?
- Violet light
- Green light
- Blue light
- Red light
Correct Answer: 2
Explanation:
- Chlorophylls a and babsorb light most strongly in the blue (430-450 nm) and red (640-680 nm)
- Green light (500-600 nm)is minimally absorbed and is mostly reflected, which is why plants appear green.
- Violet light– Absorbed moderately.
- Therefore, the correct answer is Green light→ Option 2.
Question 19
White bud of maize is due to:
- Mg
- Zn
- Ca
- Fe
Correct Answer: 2
Explanation:
- White bud of maizeis caused by zinc (Zn) deficiency.
- Symptoms: Young leaves become pale yellow to white (bleached), especially near the base; internodes shorten; plants may die.
- Mg– Interveinal chlorosis in older leaves.
- Ca– Death of growing points, leaf tip burn.
- Fe– Interveinal chlorosis in young leaves.
- Therefore, the correct answer is Zn→ Option 2.
Question 20
Plant virus containing DNA is:
- Potato mosaic virus
- Tobacco mosaic virus
- Cauliflower mosaic virus
- Papaya ring spot virus
Correct Answer: 3
Explanation:
- Cauliflower mosaic virus (CaMV)– A dsDNA (double-stranded DNA) virus, belonging to the family Caulimoviridae.
- Potato mosaic virus, Tobacco mosaic virus (TMV), Papaya ring spot virus– All have ssRNA
- Therefore, the correct answer is Cauliflower mosaic virus→ Option 3.
Question 21
The modern technique for varietal identification is:
- Electrophoresis
- Grow-out test
- Phenol test
- Polysaccharide
Correct Answer: 1
Explanation:
- Electrophoresis– A modern, rapid, and reliable technique for varietal identification based on protein or DNA banding patterns.
- Grow-out test– Traditional field test for genetic purity (time-consuming).
- Phenol test– Chemical test for seed colour reaction (limited to certain crops).
- Polysaccharide– Not a varietal identification technique.
- Therefore, the correct answer is Electrophoresis→ Option 1.
Question 22
Light reactions of photosynthesis take place in:
- Cristae
- Cytoplasm
- Mitochondria
- Thylakoids
Correct Answer: 4
Explanation:
- Light reactions(light-dependent reactions) of photosynthesis occur in the thylakoid membranes of chloroplasts (containing chlorophyll and other pigments).
- Cristae– Inner mitochondrial membrane.
- Cytoplasm– Site of glycolysis.
- Mitochondria– Site of cellular respiration.
- Therefore, the correct answer is Thylakoids→ Option 4.
Question 23
Noble cane is:
- Saccharum officinarum
- Saccharum robustum
- Saccharum sinense
- Saccharum spontaneum
Correct Answer: 1
Explanation:
- Noble cane– Refers to Saccharum officinarum, which has thick stems, high sugar content, and is the primary cultivated sugarcane species.
- robustum– A wild relative, thick but low sugar.
- sinense– Thin, hardy, used in some regions.
- spontaneum– Wild, thin, low sugar, used in breeding for hardiness.
- Therefore, the correct answer is Saccharum officinarum→ Option 1.
Question 24
The enzyme responsible for prediction of viability through Tetrazolium test is:
- Peroxidase
- Amylase
- Super oxide dismutase
- Dehydrogenase
Correct Answer: 4
Explanation:
- Tetrazolium test (TZ test)– A seed viability test that uses 2,3,5-triphenyl tetrazolium chloride.
- The test is based on the activity of dehydrogenase enzymesin living tissues. Dehydrogenases reduce the colorless tetrazolium salt to red formazan.
- Peroxidase, amylase, superoxide dismutase– Not detected by TZ test.
- Therefore, the correct answer is Dehydrogenase→ Option 4.
Question 25
An Alloaugamous oilseed is:
- Safflower
- Groundnut
- Sesame
- Mustard
Correct Answer: 1
Explanation:
- Alloaugamous– A plant that is cross-pollinated (allogamous). Among oilseeds, safflower is cross-pollinated (pollinated by insects).
- Groundnut, sesame, mustard– Primarily self-pollinated (autogamous).
- Therefore, the correct answer is Safflower→ Option 1.
Question 26
The ecological suicide of the crop seeds occur at field due to accumulation of:
- HCN
- Ethylene
- Carbon monoxide
- Carbon disulphide
Correct Answer: 1
Explanation:
- Ecological suicide– Germination of seeds in the field under unfavorable conditions (e.g., after rainfall) followed by desiccation, leading to death.
- In some crops (e.g., sorghum), seeds can accumulate HCN (hydrogen cyanide), which can cause toxicity. However, “ecological suicide” often refers to premature germination (vivipary) or seed death.
- Given the options, HCNis associated with seed toxicity.
- Therefore, the correct answer is HCN→ Option 1.
Question 27
The element which is involved in energy transfer and storage in plants is:
- N
- P
- K
- Ca
Correct Answer: 2
Explanation:
- Phosphorus (P)– A key component of ATP (energy currency) , NADPH, and other energy-transfer molecules. It is also part of nucleic acids and phospholipids.
- N– Component of proteins, nucleic acids.
- K– Osmotic regulation, enzyme activation.
- Ca– Cell wall structure, signaling.
- Therefore, the correct answer is P→ Option 2.
Question 28
Synaptonemal complex appears during:
- Leptotene
- Zygotene
- Diakinesis
- Diplotene
Correct Answer: 2
Explanation:
- Synaptonemal complex– A protein structure that forms between homologous chromosomes during synapsis.
- It appears during zygotene(the stage of prophase I where homologous chromosomes begin to pair).
- Leptotene– Chromosomes condense; no pairing.
- Diakinesis– Terminalization of chiasmata.
- Diplotene– Chiasmata visible, homologous chromosomes begin to separate.
- Therefore, the correct answer is Zygotene→ Option 2.
Question 29
The second generation Bt cotton contains genes of:
- Cry 1 Ac, Cry 2 Ab
- Cry 2 Ac, 2 Ab
- Cry 2 Ac, Cry 1 Ab
- Cry 1 Ac, 1 Ab
Correct Answer: 1
Explanation:
- First generation Bt cotton– Contained a single gene, Cry 1 Ac (active against bollworms).
- Second generation Bt cotton– Contains two genes: Cry 1 Ac and Cry 2 Ab (or Cry 1 Ac and Cry 2 Ab) for better insect resistance and to delay resistance development.
- Therefore, the correct answer is Cry 1 Ac, Cry 2 Ab→ Option 1.
Question 30
Masanobu Fukuoka is the pioneer of:
- Conservation farming
- Organic farming
- Natural farming
- Chemical farming
Correct Answer: 3
Explanation:
- Masanobu Fukuoka (1913-2008)– A Japanese farmer and philosopher, known as the pioneer of “Natural Farming” (do-nothing farming) .
- His method emphasizes no tillage, no fertilizers, no pesticides, and no weeding (as much as possible).
- Conservation farming– Focuses on soil conservation.
- Organic farming– Avoids synthetic inputs but may use tillage.
- Chemical farming– Conventional agriculture.
- Therefore, the correct answer is Natural farming→ Option 3.
Question 31
Azure blue colour tag is enclosed with the seed bag of:
- Certified seed
- Foundation seed
- Breeder seed
- Nucleus seed
Correct Answer: 3
Explanation:
- In the Indian seed certification system:
- Breeder seed– Azure blue
- Foundation seed– White tag.
- Certified seed– Golden brown (or blue for some crops).
- Nucleus seed– No tag.
- Therefore, the correct answer is Breeder seed→ Option 3.
Question 32
The enzyme involved in transcription is:
- RNA polymerase
- Taq polymerase
- DNA polymerase I
- DNA polymerase III
Correct Answer: 1
Explanation:
- Transcription– The process of synthesizing RNA from a DNA template. It is catalyzed by RNA polymerase.
- Taq polymerase– Used in PCR (DNA amplification).
- DNA polymerase I and III– Involved in DNA replication.
- Therefore, the correct answer is RNA polymerase→ Option 1.
Question 33
The highest % N is present in:
- Urea
- Ammonium nitrate
- Urea sulphate
- Anhydrous ammonia
Correct Answer: 4
Explanation:
- Anhydrous ammonia (NH₃)– Contains 82% N (highest among nitrogenous fertilizers).
- Urea (CO(NH₂)₂)– Contains 46% N.
- Ammonium nitrate (NH₄NO₃)– Contains 33-35% N.
- Urea sulphate– Lower N content (around 30-35%).
- Therefore, the correct answer is Anhydrous ammonia→ Option 4.
Question 34
Seed Act was formulated and enacted during:
- 1966 and 1968
- 1966 and 1969
- 1963 and 1966
- 1988 and 1990
Correct Answer: 1
Explanation:
- The Seeds Act, 1966was passed by the Indian Parliament in 1966 and came into force in 1968.
- It regulates the quality of seeds sold in India and establishes the Central Seed Certification Board.
- Therefore, the correct answer is 1966 and 1968→ Option 1.
Question 35
The total number of codons are:
- 60
- 62
- 64
- 66
Correct Answer: 3
Explanation:
- The genetic code consists of 64 codons(triplet combinations of four nucleotides: 4³ = 64).
- Out of these, 61 codonscode for amino acids, and 3 codons are stop codons (UAA, UAG, UGA).
- Therefore, the correct answer is 64→ Option 3.
Question 36
Which state leads in acreage and productivity of Indian mustard?
- Rajasthan
- Madhya Pradesh
- Punjab
- Uttar Pradesh
Correct Answer: 1
Explanation:
- Rajasthanis the leading state in India in terms of both acreage and productivity of Indian mustard (Brassica juncea).
- The state accounts for nearly 50% of the total mustard area in India.
- Madhya Pradesh, Punjab, Uttar Pradesh– Also produce mustard but less than Rajasthan.
- Therefore, the correct answer is Rajasthan→ Option 1.
Question 37
An example for slow releasing N fertilizer is:
- S coated urea
- AM
- N serve
- PSB
Correct Answer: 1
Explanation:
- S coated urea (Sulfur-coated urea)– A slow-release nitrogen fertilizer. The sulfur coating gradually breaks down, releasing urea slowly over time.
- AM– Not a standard slow-release fertilizer.
- N serve (Nitrapyrin)– A nitrification inhibitor, not a slow-release fertilizer.
- PSB (Phosphate Solubilizing Bacteria)– Biofertilizer for phosphorus.
- Therefore, the correct answer is S coated urea→ Option 1.
Question 38
During DNA replication, the enzyme which separates the two sides of the helix is called as:
- DNA polymerase
- DNA amylase
- DNA ligase
- DNA helicase
Correct Answer: 4
Explanation:
- DNA helicase– The enzyme that unwinds and separates the two strands of the DNA double helix by breaking hydrogen bonds between base pairs.
- DNA polymerase– Synthesizes new DNA strands.
- DNA ligase– Joins Okazaki fragments.
- DNA amylase– Not a real enzyme (amylase breaks down starch).
- Therefore, the correct answer is DNA helicase→ Option 4.
Question 39
The Electron Microscope was invented by:
- Knoll and Ruska
- Clark and Adams
- Watson and Crick
- Robert Koch
Correct Answer: 1
Explanation:
- The electron microscopewas invented by Ernst Ruska and Max Knoll in 1931.
- Ruskareceived the Nobel Prize in Physics in 1986 for this invention.
- Watson and Crick– Discovered DNA double helix.
- Robert Koch– Developed Koch’s postulates.
- Therefore, the correct answer is Knoll and Ruska→ Option 1.
Question 40
Barbara McClintock was awarded Nobel Prize in 1984 for the discovery of:
- Split genes
- Pseudo genes
- Jumping genes
- Overlapping genes
Correct Answer: 3
Explanation:
- Barbara McClintockdiscovered transposable elements (jumping genes) in maize (corn) in the 1940s-1950s.
- She was awarded the Nobel Prize in Physiology or Medicine in 1983(not 1984; the question has a typo).
- Split genes– Discovered by Richard Roberts and Phillip Sharp (Nobel 1993).
- Pseudo genes– Non-functional copies of genes.
- Overlapping genes– Genes that share nucleotide sequences.
- Therefore, the correct answer is Jumping genes→ Option 3.
